54 research outputs found

    Semi-algebraic and semi-linear Ramsey numbers

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    An rr-uniform hypergraph HH is semi-algebraic of complexity t=(d,D,m)\mathbf{t}=(d,D,m) if the vertices of HH correspond to points in Rd\mathbb{R}^{d}, and the edges of HH are determined by the sign-pattern of mm degree-DD polynomials. Semi-algebraic hypergraphs of bounded complexity provide a general framework for studying geometrically defined hypergraphs. The much-studied semi-algebraic Ramsey number Rrt(s,n)R_{r}^{\mathbf{t}}(s,n) denotes the smallest NN such that every rr-uniform semi-algebraic hypergraph of complexity t\mathbf{t} on NN vertices contains either a clique of size ss, or an independent set of size nn. Conlon, Fox, Pach, Sudakov, and Suk proved that R_{r}^{\mathbf{t}}(n,n)<\mbox{tw}_{r-1}(n^{O(1)}), where \mbox{tw}_{k}(x) is a tower of 2's of height kk with an xx on the top. This bound is also the best possible if min{d,D,m}\min\{d,D,m\} is sufficiently large with respect to rr. They conjectured that in the asymmetric case, we have R3t(s,n)<nO(1)R_{3}^{\mathbf{t}}(s,n)<n^{O(1)} for fixed ss. We refute this conjecture by showing that R3t(4,n)>n(logn)1/3o(1)R_{3}^{\mathbf{t}}(4,n)>n^{(\log n)^{1/3-o(1)}} for some complexity t\mathbf{t}. In addition, motivated by results of Bukh-Matou\v{s}ek and Basit-Chernikov-Starchenko-Tao-Tran, we study the complexity of the Ramsey problem when the defining polynomials are linear, that is, when D=1D=1. In particular, we prove that Rrd,1,m(n,n)2O(n4r2m2)R_{r}^{d,1,m}(n,n)\leq 2^{O(n^{4r^2m^2})}, while from below, we establish Rr1,1,1(n,n)2Ω(nr/21)R^{1,1,1}_{r}(n,n)\geq 2^{\Omega(n^{\lfloor r/2\rfloor-1})}.Comment: 23 pages, 1 figur

    Hasse diagrams with large chromatic number

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    For every positive integer nn, we construct a Hasse diagram with nn vertices and chromatic number Ω(n1/4)\Omega(n^{1/4}), which significantly improves on the previously known best constructions of Hasse diagrams having chromatic number Θ(logn)\Theta(\log n). In addition, if we also require that our Hasse diagram has girth at least k5k\geq 5, we can achieve a chromatic number of at least n12k3+o(1)n^{\frac{1}{2k-3}+o(1)}. These results have the following surprising geometric consequence. They imply the existence of a family C\mathcal{C} of nn curves in the plane such that the disjointness graph GG of C\mathcal{C} is triangle-free (or have high girth), but the chromatic number of GG is polynomial in nn. Again, the previously known best construction, due to Pach, Tardos and T\'oth, had only logarithmic chromatic number.Comment: 11 pages, 1 figur
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